2+cos(4x)=2sin^2(x)

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Solution for 2+cos(4x)=2sin^2(x) equation:


Simplifying
2 + cos(4x) = 2sin2(x)

Remove parenthesis around (4x)
2 + cos * 4x = 2sin2(x)

Reorder the terms for easier multiplication:
2 + 4cos * x = 2sin2(x)

Multiply cos * x
2 + 4cosx = 2sin2(x)

Multiply in2s * x
2 + 4cosx = 2in2sx

Solving
2 + 4cosx = 2in2sx

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 4cosx = -2 + 2in2sx

Combine like terms: 2 + -2 = 0
0 + 4cosx = -2 + 2in2sx
4cosx = -2 + 2in2sx

Divide each side by '4osx'.
c = -0.5o-1s-1x-1 + 0.5in2o-1

Simplifying
c = -0.5o-1s-1x-1 + 0.5in2o-1

Reorder the terms:
c = 0.5in2o-1 + -0.5o-1s-1x-1

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